1.5b^2+7=20

Solution for 1.5b^2+7=20 equation:

1.5b^2+7=20

We move all terms to the left:

1.5b^2+7-(20)=0

We add all the numbers together, and all the variables

1.5b^2-13=0

a = 1.5; b = 0; c = -13;
Δ = b2-4ac
Δ = 02-4·1.5·(-13)
Δ = 78
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{78}}{2*1.5}=\frac{0-\sqrt{78}}{3}
=-\frac{\sqrt{}}{3}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{78}}{2*1.5}=\frac{0+\sqrt{78}}{3}
=\frac{\sqrt{}}{3}
$